Question

if the difference of the roots of the equation x^2-(a+1)x+a-1=0 is equal to their products then prove that a=2

Answer 1

Answer:

this question is wrong because of 2x^2-(a+1)x+(a-1)=0

2x^2-(2+1)x+(2-1)=0

2x^2-3x+1=0

2x^2-2x-x+1=0

2x(x-1)-1(x-1)=0

2x-1=0 and (x-1)=0

X=1/2 and X=1

product of the roots c/a=(a-1)/2 and sum of th roots -b/a=(a+1)/2

(x-y)^2 and substitute in this formula of above product and sum values...