Question

if the difference of the roots of the equation x2-bx +c=0 be 1 then
(a) b2-4c,+1=0
(b) b2+4c=0
(c) b2-4c -1=0
(d) b2-4c=0
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Answer 1

Answer:

b² - 4c = 1

Completing the question: We have to find the relation between b and c.

Step-by-step explanation:

The given quadratic equation is

x² - bx + c = 0 .... (1)

If p, q be the roots of (1), then

p + q = b ..... (2)

pq = c ..... (3)

Also given,

p - q = 1

Squaring both sides, we get

(p - q)² = 1²

or, (p + q)² - 4pq = 1, since (a - b)² = (a + b)² - 4ab

or, b² - 4c = 1

This is the required relation between b and c.

Answer 2

Answer:

option c)

Step-by-step explanation:

hope it helps