Question

if the difference of theroots of the quadratic equation x (x+k) +12=0 is 1 then the positive value of k is​

Answer 1

Answer:

k=(-13)

Step-by-step explanation:

x(x+k)+12=0

putting x=1 in the above equation

:.1(1+k)+12=0

1×1+1×k+12=0

1+1k+12=0

1+1k= -12

1k= -12-1

1k= -13

k= -13/1

k= -13

The value of k= -13