Question

If the difference of two number is 5 and difference of their squares is 300, then sum of the numbers​

Answer 1

Answer:

60

Explanation:

let the numbers be x and y

given:

x-y = 5 ..........(i)

x²-y²= 300 ..........(ii)

from equation (ii)

x²-y²=300

=> (x+y)(x-y) = 300 ......[by formula]

=>(x+y) = 300/(x-y)

=>(x+y) = 300/5

=> x+y = 60

Therefore Sum of the two numbers x and y is 60

Answer 2

60 is the suitable answer.

Given:

• permit the numbers be x and y,
• the distinction among  numbers is 5 => x-y = 5.
• distinction in their squares is 300 => x²-y²= 300.

Solution:

• Simplify every aspect of the equation via way of means of eliminating parentheses and mixing like terms.
• Use addition or subtraction to isolate the variable time period on one aspect of the equation.
• Use multiplication or department to clear up for the variable.
• from the above equations, we get
• x²-y²=300
• => (x+ y)(x-y) = 300 [by formula]
• =>(x +y) = 300/(x-y)
• =>(x +y) = 300/5
• => x +y = 60

Therefore, the sum of the two numbers x and y is 60.

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