Question

If the difference of two numbers is 8 and their product is 12, what is the sum of their squares?

Answer 1

Answer:

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Answer 2

The sum of their squares is 88.

Step-by-step explanation:

Since we have given that

Let the numbers be 'x' and 'y'.

Difference of two numbers = 8

So, it becomes,

$x-y=8$ ------------------(1)

Product = 12

$xy=12$--------------(2)

Squaring the eq(1), we get that

$(x-y)^2=8^2\\\\x^2+y^2-2xy=64\\\\x^2+y^2-2\times 12=64\\\\x^2+y^2-24=64\\\\x^2+y^2=64+24\\\\x^2+y^2=88$

Hence, the sum of their squares is 88.

# learn more:

The sum of the digits of a two-digit number is 8 and the product of the digit is 12.What is the difference between the digits of that number

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