if the difference of two supplementary angles is 10 then find the angles
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Answered by
3
Let the angles be x ,x+10
sum of supplementary angles=180degres
So x+(x+10)=180
2x+10=180
2x=180-10
x=170/2
x=85
so the angles= x=85degrees and x+10=85+10=9degrees
sum of supplementary angles=180degres
So x+(x+10)=180
2x+10=180
2x=180-10
x=170/2
x=85
so the angles= x=85degrees and x+10=85+10=9degrees
Answered by
3
let the first angle be x
then the second angle be x-10
we know that supplementary angle measures 180
x+x-10=180
2x = 180+ 10
2x=190
x= 190÷2
x= 95
first angle x = 95
second angle = x-10=95-10
=85
then the second angle be x-10
we know that supplementary angle measures 180
x+x-10=180
2x = 180+ 10
2x=190
x= 190÷2
x= 95
first angle x = 95
second angle = x-10=95-10
=85
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