Question

if the diffrence of the zeros of the quadratic polynomial x^2+kx+12 is 1 then find the value of k

Answer 1

$f(x) = {x}^{2} + kx + 12 \\ \\ f(1) = 0 \: \: \: \: \: \because \: 1 \: is \: zero \: of \: f(x) \\ \\ {1 }^{2} + k(1)+ 12 = 0 \: \: \: \: \\ \\ k + 13 = 0 \\ \\ \\ k = - 13 \\ \\ hope \: it \: helps \: you$