Question

if the diffrence of two digit number and number obtained by reversing the digit is 27 find the different between the digit of 2digit number​

Answer 1

Answer:

Hope the above attachment helps you, mark me as the brainliest.

Answer 2

Step-by-step explanation:

Let the two digit number is pq on reversing the number we get qp

• therefore, pq - qp =27.

In first number pq, p is at the place of tens and q is at unity.

• Therefore it's value is =(10p + q)

In second case value is reversed,

• so qp =( 10q + p)

Hence difference between two digits is:

$(10p + q) - (10q + p) = 27$

$10p + q - 10q - p = 27 \\ 10p - p + q - 10q = 27 \\ 9p - 9q = 27$

$9(p - q) = 27 \\ p - q = \frac{27}{9} = 3 \\ p - q = 3$

• Also digit is 96.
• It's reverse is 69,
• so their difference is 96–69=27,
• and 9–6=3

hope it helps u