If the digit 1 placed, after a two digit number whose tens digit is 'a' and units digit its 'b' if the sum of the place values of the digit is 191 then write the equation.
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100t+10u+1
Placing 1 after two digit number is the indication that,
shift the given digit towards left, so that t is now hundred's digit and u is now tens digit so the value becomes 100t+10u+1
So 100t+10u+1 is correct answer
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