If the digit in the units place of two digit number is '2x' and digit in the the ten's place is 'y' then the two digits number is [2xy, 2x+y , 2x+10y, 20x+y]
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Step-by-step explanation:
Let x denote the digit in the tenth place and y denote the digit in unit place.. So, the number may be written as x y 10 + in the expanded form. (just like 35= 10(3) +5)
When the digits are reversed, x becomes the digit in unit place and y becomes the digit in the tenth place. The changed number, in the expanded form is 10y+x.
According to the first condition, we have y=2x which is written as
2x−y=0 (1)
Also, by second condition, we have
(10+x)−(10x+y)=27
That is, −9x+9y=27→−x+y=3 (2)
Adding equations (1) and (2), we get x= 3.
Substituting x 3 = in the equation (2), we get y = 6.
Thus, the given number is (3×10)+6=36.
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Answer:
prove that √7 is irrational.
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