Math, asked by sanjayvr013, 8 months ago

If the digits of a two-digit number are interchanged, the number so formed is 18 more than the original number. The sum of digits is 8. What is the thrice value of original number? METHODS

Answers

Answered by Anonymous
7

Answer:

\huge\underbrace\mathbb\blue{AnSwEr}

<b><marquee>

As given,

10y + x-10x-y=18

=> 9(y -x) = 18

=>y-x = 2....(1)

Again, x + y = 8 ...(ii)

From (i) and (ii)

2y = 10

=>y = 5

\( \Large \therefore \)x = 3 [from(i)]

Number=10x + y =\(\Large 10 \times 3 \)+ 5 = 35

Answered by tennetiraj86
5

Answer:

answer for the given problem is given

Attachments:
Similar questions