If the digits of a two-digit number are interchanged, the number so formed is 18 more than the original number. The sum of digits is 8. What is the thrice value of original number? METHODS
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Answered by
7
Answer:
As given,
10y + x-10x-y=18
=> 9(y -x) = 18
=>y-x = 2....(1)
Again, x + y = 8 ...(ii)
From (i) and (ii)
2y = 10
=>y = 5
\( \Large \therefore \)x = 3 [from(i)]
Number=10x + y =\(\Large 10 \times 3 \)+ 5 = 35
Answered by
5
Answer:
answer for the given problem is given
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