Question

If the digits of a two-digit number are interchanged, the number so formed is 18 more than the original number. The sum of digits is 8. What is the thrice value of original number?


Please answer fast!

Answer 1

Answer:

for example

a+b=6⟹b=6−a

10b+a=10a+b+14

⟹9b−9a=14

⟹9(6−a)−9a=14

⟹54−18a=14

⟹−18a=−40

⟹a=4018

a=229⟹b=379

Seems highly unlikely that this is a two-digit number number since the digits aren't integers, but I'll play along.

10a+b⟹10(2+29)+3+79

⟹20+209+3+79

⟹23+279=23+3=26

62=26+36

36≠14

2+6≠6

I assume that thrice the original number would be 78 if 26 was the original number, but there are no two-digit numbers that conform to all the conditions given.