If the dimensions of a cuboid are 5cm*4cm*5.5cm. find the total surface area of the cuboid.Explain
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Step-by-step explanation:
(1) length =12 cm breadth =10 cm height =5 cm
TSA=2(lb+bh+lh)=2[12×10+10×5+5×12]
TSA=2[120+50+60]=2×230
[TSA=460cm
2
]
(2) length =5 cm breadth =3.5 cm height =1.4 cm
TSA=2(lb+bh+lh)=2[5×3.5+3.5×14+1.4×5]
TSA=2[17.5+4.90+7.0]=2[29.4]
[TSA=58.8cm
2
]
(3) length =2.5 cm breadth =2 m height =2.4 m
TSA=2(lb+bh+lh)=2[0.025×2+2×2.4+2.4×0.025]
TSA=2[0.05+4.8+0.0600]=2[4.91]
(4) length =8 m breadth =5 m height =3.5 m
TSA=2(lb+bh+lh)=2[8×5+5×3.5+3.5×8]
TSA=2[40+17.5+28.0]=2[85.5]
[TSA=171.0m
2
]
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