Question

if the
dingonal of a parallelogram are
equal
then
Show
that
it
is a rectangle​

Answer 1

Prove:

Given: A parallelogram ABCD, in which AC = BD  

TO Prove: ABCD  is a rectangle.

Proof: In △ABC and △ABD

AB = AB [common]

AC = BD [given]

BC = AD [opp . sides of a | | gm]

⇒ △ABC ≅ △BAD [ by SSS congruence axiom]

⇒ ∠ABC = △BAD [c.p.c.t.]

Also, ∠ABC + ∠BAD = 180° [co - interior angles]

⇒ ∠ABC + ∠ABC = 180° [∵ ∠ABC = ∠BAD]

⇒ 2∠ABC = 180°  

⇒ ∠ABC = 1 /2 × 180° = 90°  

Hence, parallelogram ABCD is a rectangle.

Answer 2

Answer:

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