Question

If the discriminant is greater than zero, the quadratic equation has two real and equal roots?

Answer 1

Answer:When a,b,c are real numbers, a is not equal to zero and discriminant is negative (i. e b2 -4ac < 0)

Then the roots a and b of the quadratic equation ax2 +bx+c = 0 are unequal and imaginary

So c) imaginary is the answer (it is unequal )

Please mark me as the brainliest answer

Step-by-step explanation:

Answer 2

The quadratic formula states that:

x=

−b±

√

b2−4ac

2a

The part we're interested in is b2−4ac this is called the discriminant.

I know from school that we can use the discriminant to figure out how many zeroes a quadratic equation has (or rather, if it has complex, real, or repeating zeroes).

If b2−4ac>0 then the equation has 2 real zeroes.

If b2−4ac<0 then the equation has 2 complex zeroes.

If b2−4ac=0 then the equation has repeating zeroes.