Math, asked by riajfernandis, 11 months ago

If the discriminant of quadratic equation b² - 4ac=o then the roots are​

Answers

Answered by saquibsiddiqui
22

Answer:

Equal

Step-by-step explanation:

Let a quadratic polynomial be ax^2 + bx + c = 0

Since discrimination of a quadratic polynomial is:

D = b^2 - 4ac

And it is given that:

D = 0

Now,

x = (- b ± √D)/2a

Since D = 0

Therefore,

x = (- b ± √0)/2a

x = (- b ± 0)/2a

x = - b/2a

And from this both roots/zeroes are equal.

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Answered by pulakmath007
1

If the discriminant of quadratic equation b² - 4ac = 0 then the roots are real and equal

Given :

The discriminant of quadratic equation b² - 4ac = 0

To find :

The nature of the roots of the quadratic equation

Concept :

A general equation of quadratic equation is

ax² + bx + c = 0

Now one of the way to solve this equation is by SRIDHAR ACHARYYA formula

For any quadratic equation ax² + bx + c = 0

The roots are given by

 \displaystyle \sf x =  \frac{ - b \pm \:  \sqrt{ {b}^{2} - 4ac } }{2a}

Solution :

Step 1 of 3 :

Write down the given data

Let us consider the quadratic equation as

ax² + bx + c = 0

Now it is given that the discriminant of quadratic equation b² - 4ac = 0

Step 2 of 2 :

Find nature of the roots of the quadratic equation

By Sridhar Acharyya formula the roots are given by

 \displaystyle \sf x =  \frac{ - b \pm \:  \sqrt{ {b}^{2} - 4ac } }{2a}

\displaystyle \sf  \implies \: x =  \frac{ - b \pm \: 0  }{2a} \:  \:  \: \bigg[ \:  \because \:{b}^{2} - 4ac  = 0 \bigg]

\displaystyle \sf{ \implies x =  -  \frac{b}{2a}  \: , \:  -  \frac{b}{2a}}

So the roots of the quadratic equation are real and equal

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