Question

If the discriminant of quadratic equation b² - 4ac=o then the roots are​

Answer 1

Answer:

Equal

Step-by-step explanation:

Let a quadratic polynomial be ax^2 + bx + c = 0

Since discrimination of a quadratic polynomial is:

D = b^2 - 4ac

And it is given that:

D = 0

Now,

x = (- b ± √D)/2a

Since D = 0

Therefore,

x = (- b ± √0)/2a

x = (- b ± 0)/2a

x = - b/2a

And from this both roots/zeroes are equal.

I hope this is helpful for you....

Plzzz mark me as branliest......

Answer 2

If the discriminant of quadratic equation b² - 4ac = 0 then the roots are real and equal

Given :

The discriminant of quadratic equation b² - 4ac = 0

To find :

The nature of the roots of the quadratic equation

Concept :

A general equation of quadratic equation is

ax² + bx + c = 0

Now one of the way to solve this equation is by SRIDHAR ACHARYYA formula

For any quadratic equation ax² + bx + c = 0

The roots are given by

$\displaystyle \sf x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac } }{2a}$

Solution :

Step 1 of 3 :

Write down the given data

Let us consider the quadratic equation as

ax² + bx + c = 0

Now it is given that the discriminant of quadratic equation b² - 4ac = 0

Step 2 of 2 :

Find nature of the roots of the quadratic equation

By Sridhar Acharyya formula the roots are given by

$\displaystyle \sf x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac } }{2a}$

$\displaystyle \sf \implies \: x = \frac{ - b \pm \: 0 }{2a} \: \: \: \bigg[ \: \because \:{b}^{2} - 4ac = 0 \bigg]$

$\displaystyle \sf{ \implies x = - \frac{b}{2a} \: , \: - \frac{b}{2a}}$

So the roots of the quadratic equation are real and equal

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If 1/2 is a root of the quadratic equation x²-mx-5/4=0 , then the value of m is?

https://brainly.in/question/21062028

2.Find the roots of the quadratic equation 6x2 +5x + 1 =0 by method of completing the squares.

https://brainly.in/question/30446963

#SPJ3