Question

if the discriminant of the equation 6x^2 + bx + 2 = 0 is 1, then the value of 'b' is? ​

Answer 1

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Here's your answer..

The equation is 6x² + bx + 2 = 0 is 1..

To Find :- Value of "b".

Solution :- (b²-4 × 6 × 2)½ = 1.

Squareing both sides

=> b² – 4 × 6 × 2=1

=>b² – 48 = 1

=>b² = 48 + 1

=>b² = 49

=>b = +/ –(49)½

=>b = +/-7

Hence

b=7 or b=-7..

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