If the discriminant of the equation 6x²-bx+2=0 is 1,then find the value of of th
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I think the question is incomplete..!
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Answer:
Step-by-step explanation:
D=1
b²-4ac=1
where, a=6
b=-b
c=2
Putting all the values in D=1
(-b)²-4(6)(2)=1
b²-48=1
b²=49
b=7
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