Question

If the discriminant of the equation kx^2-3root2x+4root2=0 is 14,then find the value of k.

Answer 1

Answer:

So, rhe value of K= 1/4√2

Step-by-step explanation:

Given equation-:

Kx²-(3√2)x+4√2

Discriminant-:

b²-4ac=14

To find-:

Value of K

Solution-:

Discriminant = b²-4ac

=>14 = (3√2)²-4K*4√2

=>14 = 18-16K√2

=> -4 = -(16√2)K

=> K = 1/4√2

Answer 2

Answer:

Value of k is  1 / 4$\sqrt{2}$

Step-by-step explanation:

Equation is k$x^{2}$ -3$\sqrt{2}$ x +4$\sqrt{2}$=0

General eq. of quadratic eq . is a$x^{2}$ +bx+c =0

By comparing we get a= k . b= - 3$\sqrt{2}$ , c= 4$\sqrt{2}$

We know that ,

D= $b^{2}$ -4ac

14 = $(3\sqrt{2)} ^{2}$ - 4× k× 4$\sqrt{2}$       (given D = 14)

14 = 18 - 16$\sqrt{2}$ k

16$\sqrt{2}$ k = 18 -14

      k = 4 /16$\sqrt{2}$

          = 1/ 4$\sqrt{2}$