if the discriminat of 6^x-bx+2=0 is 1 then the value of b is
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Answer:
DiscriminantΔ=b
2
−4ac
Given:Discriminant =1
⇒b
2
−4ac=1 where a=6,b=b,c=2
⇒b
2
−4×6×2=1
⇒b
2
−48=1
⇒b
2
=1+48=49
∴b=±7
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