Question

If the discriminate of the equation kx^2 -3root2x +4root2 = 0 is 14 , then find the value of know

Answer 1

kx²-3√2x+4√2=0
D=b²-4ac
0=(-3√2)² -4×k×4√2
0=18-16√2k
0=2(9-8√2k)
0=9-8√2k
-9=-8√2k
9=8√2k
9/8√2=k
$k = 9 \div 8 \sqrt{2}$

Answer 2

The value of k is $k=\frac{1}{4\sqrt2}$.

Step-by-step explanation:

Given : If the discriminate of the equation $kx^2 -3\sqrt{2x} +4\sqrt{2}= 0$ is 14.

To find : The value of k ?

Solution :

The discriminant of the quadratic equation $ax^2+bx+c=0$ is  $D=b^2-4ac$.

Here, a=k, b=$-3\sqrt{2}$ , $c=4\sqrt{2}$ and D=14.

Substitute the values,

$14=(-3\sqrt2)^2-4(k)(4\sqrt2)$

$14=18-16\sqrt{2} k$

$16\sqrt{2} k=18-14$

$16\sqrt{2} k=4$

$k=\frac{4}{16\sqrt2}$

$k=\frac{1}{4\sqrt2}$

Therefore, the value of k is $k=\frac{1}{4\sqrt2}$.

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