Question

if the discriminationant of the equation 6x^2-bx-2=0 is 1 find the value b​

Answer 1

Answer:

± √47 i

Step-by-step explanation:

Discriminant of the equation 6x² - bx - 2 = 0 is 1

Comparing equation with Ax² + Bx + C we get,

• A = 6
• B = - b
• C = - 2

⇒ Discriminant = 1

⇒ B² - 4AC = 1

⇒ ( - b )² - 4( 6 )( - 2 ) = 1

⇒ b² + 48 = 1

⇒ b² = 1 - 48

⇒ b² = - 47

⇒ b = ± √(-47)

⇒ b = ± √47 i

[ i = √-1 ]

So we don't have real solution

Therefore the value of b is ± 47 i .