Question

If the displacement of a body is given byX= k0+ k1t/2-k2t^2/3 then it's acceleration is

Answer 1

Answer:

Acceleration = 4/9 . t⁻⁴/³  m/s²

Explanation:

              Displacement   X = k0 + k t/2 - k 2 t²/³

               Velocity = dX / dt = 0+ k/2 - 2/3 . k. 2. t⁻¹/³

                                dX / dt = k/2 - 4/3 . k . t⁻¹/³

                Acceleration = d²X / dt² = 0 - 4/3 . (-1/3) . t⁻⁴/³

                                Acceleration = 4/9 . t⁻⁴/³ m/s²