if the displacement of a body is proportional to the cube of the time, then the body has what acceleration?
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let displacement is x , and time is t.
then,
x. -- ---> t^3
differentiating both side w.r.to time t,
dx/dt = d(t^3)/dt = 3 t^2
velocity,. v ----> 3t^2
again differentiating both side w.r.to time t,
dv/dt = 3×2×t^1
acceleration, a ---->6t
hence,
the acceleration should also vary with time and it increases with time.
then,
x. -- ---> t^3
differentiating both side w.r.to time t,
dx/dt = d(t^3)/dt = 3 t^2
velocity,. v ----> 3t^2
again differentiating both side w.r.to time t,
dv/dt = 3×2×t^1
acceleration, a ---->6t
hence,
the acceleration should also vary with time and it increases with time.
realsujaykumar:
I hope you like this ...plz mark as brainliest
Thanks. So the way the question was originally asked, your answer would imply that the acceleration would be increasing? It was a multiple choice question and some choices were uniform acceleration, increasing acceleration, uniform velocity... u get the point.
How do i mark as brainliest?
the answer should be increasing acceleration
according to your question there is no requirements of duing all that
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