Question

If the displacement of the particle is given by x=A+Bt^2, find the velocity at t=2s

Answer 1

Answer:

please mark me brainliest

Explanation:

Position of the particle x=2t

2

−t

3

Velocity v=

dt

dx

=4t−3t

2

Acceleration a=

dt

dv

=4−6t

So, a( at t=2 s)=4−6×2=−8 m/s

2

Since, acceleration is depending on the time. SO, acceleration is not constant

Answer 2

Answer:

4B m/s

Explanation:

v=dx/dt=d/dt(A+Bt^2)=0+B×2t=2B×2=4B m/s.