If the distanc e between the two points (8,x) and(x, 8) is 2√2 units then find the value of x
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Answer:
x=6(or)10
Step-by-step explanation:
√((x2-x1)^2+(y2-y1)^2)=d
square on both side
(x-8)^2+(8-x)^2=8
x^2+64-16x+64+x^2-16x=8
2x^2-32x+120=0
divide by 2 on both sid
x^2-16x+60=0
(x-6)(x-10)=0
so, the x=6(or)10
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