Question

If the distance b/w two electric charge s is doubled , how much will the force exerted b/w them change to ?​

Answer 1

Force is inversely proportional to square of the distance between them. Therefore,if distance between them is doubled then force reduced to 1/4 of the inital value.

Answer 2

Force is inversely proportional to square of the distance between them.

$Initial \: force...F = k \frac{q1q2}{ {r}^{2} }$

The distance b/w two electric charge is doubled.

$Final \: force...F = k \frac{q1q2}{( {2r)}^{2} }$

$F (final)= k \: \frac{q1q2}{4( {r}^{2})}$

Comparing initial with final force , this is concluded as

$F(final) = \frac{1}{4} \times F(initial)$

Therefore,if distance between them is doubled then force reduced to 1/4 of the initial value.