Question

if the distance between 2 objects is doubled, and each mass is half, than how gravitational force, between them changes?​

Answer 1

Explanation:

So, if the distance between two objects is doubled, then the gravitational force becomes

2×2

1

*That is, 1/4.

Therefore, if the distance between two masses be doubled, then the force between will becomes 1/4.

Answer 2

Answer:

• New Gravitation force between the bodies would be 1/16 th of the Initial Gravitation force.

Explanation:

Let, Initially Distance between two objects be d, and masses of objects be m₁ and m₂

Then,

Initially Gravitational force (F₁) between the objects will be,

→ F₁ = G m₁ m₂ / d²   ____eqn(1)

[ Where G is universal gravitational constant ]

Now, Distance between objects is doubled so new distance between the objects would be 2 d  and, since their masses are halved so, new masses of objects would be m₁/2 and m₂/2

so,

New Gravitational force (F₂) between the objects will be,

→ F₂ = G (m₁/2) (m₂/2) / (2d)²

[ where G is universal gravitation constant ]

→ F₂ = ( G m₁ m₂ / 4 ) / ( 4 d² )

→ F₂ = G m₁ m₂ / (16 d²)

→ F₂ = ( 1 / 16 ) (G m₁ m₂ / d²)

By equation (1)

→ F₂ = ( 1/16 ) ( F₁ )

Therefore,

• New Gravitation force between the bodies would be 1/16 th of the Initial Gravitation force.