Question

If the distance between (3.-3) and
(x-7) is 5 then x =
O a)10
Ob)1
Oc)2
O d)6.​

Answer 1

Step-by-step explanation:

$\sf{answer}$

given,

distance between (3.-3) and

(x-7) is 5

to find:-

value of 'x'

required formula:-

$d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2} }$

$\huge\sf\underline{solution}$

.: $\sf{x_2}$ = x

$\sf{x_1}$ = 3.

.: $\sf{y_2}$ = -7

$\sf{y_1}$ = -3.

.: d = √(x-3)²+(-7-(-3))² = 5

.: d = 5 given

√(x)²+2(x)(-3)+(-3)²+(-7+3)²= 5

√x²-6x+9+(-4)²= 5

√x²-6x+9+16 = 5

√x²-6x+25 = 5

.: squaring on both sides:-

(√x²-6x+25)² = (5)²

x²-6x+25= 25

x²-6x+25-25 = 0

x²-6x= 0

x(x-6) = 0

.: x = 0. or x= 6

.: according to options 'x = 6'.