Question

If the distance between A(12,0) & B(0, a) is
410 units then find the value of a. Ans: + 4​

Answer 1

ab = √(144-0) +(0-a^2 )

410 =√(144+a^2 )

168100-144=a^2

√167956=a

409.8 = a

sorry bro how it's answer is +4 but acc. to your questions right answer is this