Question

if the distance between a point (3,0) and (0,y) is 5 unit and y is positive then find a value y

Answer 1

Hello user

Using the distance formula, we have

5 = [(3)^2 + (y)^2]^1/2

25 = 9 + y^2

y^2 = 16

y = +4 and -4

Hope it works

Answer 2

first of all if y was not mentioned positive we would take it positive not negative as it is unknown. now to solve this Q used distance formula:
✓(x2-x1)^2+(y2-y1)^2

✓(0-3)^2+(y-0)^2=5

(-3)^2+y^2=25
y^2=25-9
y^2=16
y=4