If The distance between AB and DC side of a rhombus is PQ and the distance between the side AD and BC is RS. prove that PQ=RS.
Answers
Answer:
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Step-by-step explanation:
The distance between two sides AB and DC of rhombus ABCD is PQ and distance between sides AD and BC is RS
Formula used.
Opposite sides of rhombus are parallel
And all sides of are equal in rhombus
Area of triangle = × Base × Height
Draw Δ DPC by joining DP and PC and
Δ CRB by joining CR and RB in rhombus
In triangle DPC and rhombus ABCD
Both lies on same base CD
And lies between parallel lines AB || CD
⇒ Because opposite sides of rhombus are parallel
∴ Area of Rhombus ABCD = × Area of triangle DPC
In triangle CRB and rhombus ABCD
Both lies on same base BC
And lies between parallel lines BC || AD
⇒ Because opposite sides of rhombus are parallel
∴ Area of Rhombus ABCD = × Area of triangle CRB
By equating both
Area of triangle DPC = Area of triangle CRB
× PQ × CD = × RS × BC
As all sides of rhombus are equal
⇒ CD = BC
× PQ × CD = × RS × CD
∴ PQ = RS
Hence proved ;