Question

If the distance between between P(2x,-5) and Q(3x,-2) is 5 units then value of x is

Answer 1

Answer:

2x - 5 = 3x -2

2x -3x = -2 + 5

x = 3

P = 2 (3) -5 =1

Q = 3x -2 = 7

Answer 2

Answer:

4

Step-by-step explanation:

• as we know the distance formula

pq=$\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y1 )^{2}}$

put values

5=$\sqrt{(3x_{}-2x_{} )^{2} +(-2_{}-(-5) )^{2}}$

5=$\sqrt{(x )^{2} +(3)^{2}}$

take square both side

25=x²+9

x²=25-9

x²=16

x=4