If the distance between earth and sun were one-third of its present value, the number of days in a year would be?
a) 75 days b) 70 days c) 67days d) 68.5 days
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we know that
time period T = 1 year of a planet and radius = R a re related as :
T² α R³
T2² = ( R2 / R1 )³ * T1²
R2 = R1/3 given.
=> T2² = 1/27 * 365² = 4934
T2 = 70.24 days
==========================
velocity of a planet of mass m in orbit around the Sun of mass M : v
let time period = T = 2π/ω
we have v = r ω, ω = angular velocity of the rotation of the planet
let R be the radius of the orbit of the planet.
G = universal gravitational constant
centripetal force = gravitational force between Earth and Sun
m v²/R = G M m / R²
v² = G M / R
v = R ω
=> ω² = G M / R³
ω = √(GM/R³)
T = 2 π / ω = 2π /√(GM ) * √R³
or T² = 4π² / (GM) * R³
time period T = 1 year of a planet and radius = R a re related as :
T² α R³
T2² = ( R2 / R1 )³ * T1²
R2 = R1/3 given.
=> T2² = 1/27 * 365² = 4934
T2 = 70.24 days
==========================
velocity of a planet of mass m in orbit around the Sun of mass M : v
let time period = T = 2π/ω
we have v = r ω, ω = angular velocity of the rotation of the planet
let R be the radius of the orbit of the planet.
G = universal gravitational constant
centripetal force = gravitational force between Earth and Sun
m v²/R = G M m / R²
v² = G M / R
v = R ω
=> ω² = G M / R³
ω = √(GM/R³)
T = 2 π / ω = 2π /√(GM ) * √R³
or T² = 4π² / (GM) * R³
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