If the distance between origin and a point (12,x) is 13 units then find the value(s) of ‘x’
Answers
Answered by
1
i think 13।+44..................
Answered by
4
the coordinates of the point on the origin will be=(0,0).
and the distance of between the origin and the point P is=13.
the coordinates of the point p is=(12,x).
so,d=√(x2−x1)²+(y2−y1)².so square root(0-12)² + (0-x)²=13.results in,=√(-12)² + (-x)²=13.= √(144+x²)=13.
squaring both sides...
(144+x²)²=169.
by solving this equation u cn get the aprropraite answer.
and the distance of between the origin and the point P is=13.
the coordinates of the point p is=(12,x).
so,d=√(x2−x1)²+(y2−y1)².so square root(0-12)² + (0-x)²=13.results in,=√(-12)² + (-x)²=13.= √(144+x²)=13.
squaring both sides...
(144+x²)²=169.
by solving this equation u cn get the aprropraite answer.
Similar questions