Question

If the distance between p(0,6) and q(a,0) is 6 units.what will be the value of a

Answer 1

using distance formula
$\sqrt{(x2} - x1) {}^{2} + (y2 - y1) {}^{2}$
√(0-a)² + (6-0)²
√a² + 36. = 6
a² + 36 = 36
a² = 0
a = 0

Answer 2

Answer:

Step-by-step explanation: