Question

if the distance between p(2,-3) and q(10,y) is 10units find the value of y​

Answer 1

Answer:

$\large\boxed{\sf{y=3}}$

Step-by-step explanation:

Given two points are (2, -3) and (10, y).

Distance between them = 10 units

By distance formula, we have

$= > \sqrt{ {(10 - 2)}^{2} + {(y + 3)}^{2} } = 10 \\ \\ = > {8}^{2} + {(y + 3)}^{2} = {(10)}^{2} \\ \\ = > 64 + {(y + 3)}^{2} = 10 \\ \\ = > {(y + 3)}^{2} = 100 - 64 \\ \\ = {(y + 3)}^{2} = 36 \\ \\ = {(y + 3)}^{2} = {6}^{2} \\ \\ = > y + 3 = 6 \\ \\ = > y = 6 - 3 \\ \\ = > y = 3$

Hence, y = 3

Answer 2

Answer:y=3 and y=-9

Step-by-step explanation:

Answer is attached below