Question

.If the distance between (p,3) and (2,-1) is 5 units then find p?

Answer 1

Sqrt{(y2-y1)^2 + (x2-x1)^2}

5= sqrt{(-1-3)^2 + (2-p)^2}
5= sqrt{ 16 + k}

So k = 9

2-p = -3 or 3

So P = 5 or -1

Hope this helps