Question

if the distance between p (4,0) and q(0,x) is 5 unit the value of x will be​

Answer 1

Answer:

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Step-by-step explanation:

$Distance \: \: Formula: \\ \\ \sf{ \sqrt { { (x_{2} - x_{1} )} ^ 2 + {(y_{2} - y_{1}) } ^ 2 } } \\ \\ Substituting \: \: the \: \: given \: \: values , \\ \\ \sf{ \sqrt { { (0 - 4) } ^ 2 + {(x - 0) } ^ 2 } } = 5 \\ \\ =>\sf{ \sqrt { ( - 4) {}^{2} + {(x)} ^ 2 } } = 5\\ \\ => \sf{ \sqrt { 16 + {x} ^ 2 } } = 5 \\ \\ Squaring \: \: both \: sides \\ \\ =>x^2 + 16 = 25 \\ \\ => x ^ 2 = 9 \\ \\ => x = 3 \: \: and \: \: -3$