if the distance between point a(2,2)and b(-1,4) equal to 5 what is the value of x
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Answer:
We have,
P=(2,2),Q=(5,x) and PQ=5
We know that
d
2
=(x
2
−x
1
)
2
+(y
2
−y
1
)
2
Therefore,
PQ
2
=(5−2)
2
+(x−2)
2
5
2
=(3)
2
+(x−2)
2
25=9+(x−2)
2
(x−2)
2
=16
x−2=±4
x=6 or x=−2
Hence, this is the answer.
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