if the distance between point source and the screen is doubled then the intensity of light on the screen will become? explanation?
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Answer:Intensity, I∝
R
2
1
, where R is the distance between a point source of light and a screen. If R is doubled then we have
I
′
∝
4R
2
1
=
4
I
Hence intensity will be one quarter of the original value.
Explanation:
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