Question

If the distance between points A (4 , k) & B (7 ,
6) is 5 units ,then . Find the value of K

Answer 1

I think it's the answer to your question!!

Answer 2

AB^2=(x1-x2)^2+(y1-y2)^2

(5)^2=(4-7)^2+(k-6)^2

25=(-3)^2+k^2+36-12k

25=9+k^2+36-12k

25-45=k^2-12k

k^2-12k+20=0

k^2-2k-10k+20=0

k(k-2)-10(k-2)

(k-2) (k-10)

k=2 k=10

Hope it helps you....