Question

If the distance between points A(a,0)and B (0,5)is 5 units, then find the value of a

Answer 1

we apply the distaance formula,

we get, a2 + 25 = 25

a2 = 25 - 25

a2 = 0

a = 0

Answer 2

The value of a=0.

Step-by-step explanation:

Given : If the distance between points A(a,0)and B (0,5)is 5 units.

To find : The value of a ?

Solution :

The formula used to find the distance between two points is

$d = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2} }$

Where,

d is the distance d= 5

$A=(x_1, y_1)=(a,0)$

$B=(x_2, y_2)= (0,5)$

Substitute the values,

$5= \sqrt{(0-a)^{2}+(5-0)^{2}}$

$5= \sqrt{a^2+25}$

Squaring both side,

$25=a^2+25$

$a^2=0$

$a=0$

Therefore, the value of a=0.

#Learn more

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