If the distance between points (x , 0 ) and (0,3) is 5, what are values of x ?
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Answered by
13
Distance formula,
(Distance)² = (x2-x1)² + (y2-y1)²
(Distance)² = (0-x)² + (3-0)²
(5)² = (-x)² + (3)²
25 = x² + 9
x² = 16
x = ±4
(Distance)² = (x2-x1)² + (y2-y1)²
(Distance)² = (0-x)² + (3-0)²
(5)² = (-x)² + (3)²
25 = x² + 9
x² = 16
x = ±4
Answered by
1
distance between two point
(x-0)^2-(3-0)^2= 5^2
x^2=25-9
x=4
(x-0)^2-(3-0)^2= 5^2
x^2=25-9
x=4
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