Physics, asked by Adityaajain, 1 year ago

if the distance between sun and earth increases by 125% of its present value suddenly then the duration of one year will be

Answers

Answered by aachal4170
0

Explanation:

So let us suppose.

r1= initial radius

r2=final radius

r2=r1+125%r1=9/4r1

t1=initial duration of 1 year

t2=final duration of 1 year

by Kepler's law we know that t^2 is directly proportional to r^3

therefore

(t2/t1)^2=(r2/r1)^3

t2/t1=(r2/r1)^(3/2)

t2=t1*(9/4r1/r1)^(3/2)

t2=t1*(3/2)^3

t2=365*27/8

this will be the duration of 1 year if the distance of earth and sun increases by 125%.

Answered by dualadmire
0

Given:

The distance between the Sun and Earth is increased by 125% of present value

To find:

The duration of one year.

Solution:

Let us assume the initial distance between sun and earth be r.

Final distance be r'. Then:

r' = r + 125% of r

= r + 125/100 × r

= r + 1.25r

= 2.25r

From Kepler's law we know that:

Square of Duration of one year (T²) is directly proportional to r³.

Therefore:

T'²/ T² = r'³/ r³

T'² = (T²× r'³)/ r³

T'² = 365² × 2.25³

T' = 365 × 2.25^(3/2)

T' = 1231.875 days

Thus the duration if one year will be 1231.875 days.

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