Question

if the distance between the first maxima and fifth minima of a double slit experiment pattern is 7mm and the slits are separated by 0.15mm with the screen 50cm from the slits then the wavelength of the light is
​

Answer 1

Explanation:

Path difference between first maxima and fifth minima, 7×10

−3

=

2d

(2×5−1)λD

−

d

(1)λD

=

2d

7λD

λ=

7D

7×10

−3

×2d

=

7×50×10

−2

7×10

−3

×2×15×10

−5

=0.6×10

−6

m=600nm