Question

if the distance between the point (4, k) and (1, 0) is 5 units, find k​

Answer 1

Answer:

Using distance formulaAB=(x2−x1)2+(y2−y1)2

From the question

5=(1−4)2+(0−k)2

⇒25=9+k2 on squaring

⇒k2=25−9=16

∴k=±4

∴k takes 2 values{−4,+4}.

Answer 2

explaination

answer : 4,-4

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