Question

if the distance between the point (4,p) and (1,0) is 5 unit, then the value of p is?

Answer 1

Answer:

p= 4

Step-by-step explanation:

let A = ( 4,p). B = (1,0)

let x1=4 , y1= p. and x2=1 , y2=0

given AB = 5

apply distance formula, AB= √(x1-x2)^2+(y1-y2)^2

=> 5=√(4-1)^2-(p-0)^2

=> p^2=16

=> p= 4

Answer 2

Step-by-step explanation:

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