Math, asked by rishabhkashyap2407, 3 months ago

if the distance between the point (5,-2) and
(1, a) is 5, find the value of a​

Answers

Answered by sabaalig
0
Please mark as brailiest
Attachments:
Answered by ItzBrainlyBeast
39

\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTioN :-}}

\large\textsf{                                                               }

↦ Distance Formula :-

 \sqrt{( \large\textsf{x}_{2} \:  -  \:  \large\textsf{x}_{1} )^{2}   +  \: ( \large\textsf{y}_{2} \:  -  \:  \large\textsf{y}_{1})^{2}  }

\large\textsf{                                                               }

Here ,

x = 5

y = 2

x = 1

y = a

d = 5

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{5} \:  =  \:  \sqrt{\large\textsf{( \: 1 \:  -  \: 5 \:  })^{2}  \:  +  \: [ \large\textsf{\: a \:  -  \: ( \:  - 1 \: )}] ^{2}  }

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{5} \:   =  \:  \sqrt{ {\large\textsf{4}}^{2} \:  +  \: \large\textsf{( \: a \:   +  \: 1 \: )} ^{2}  }

\large\textsf{                                                               }

 \qquad\tt{:}\longrightarrow\large\textsf{25} \:  =  \:\large\textsf{ 16 }\:  +  \:  \:  {\large\textsf{a}}^{2}   \:  + \large\textsf{ \:  1  \:  -  \: 2a}\large\textsf{.... ( Squaring on both sides )}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{25} \:  =  \:\large\textsf{ 17 \:  + \:  {a}}^{2}  \:  -  \: 2a

\large\textsf{                                                               }

 \qquad\tt{:}\longrightarrow\large\textsf{25 \:  -  \: 17 \:}  =  \:  {\large\textsf{a}}^{2}  \:  - \large\textsf{ \: 2a }

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{8 \:  =  \:  {a}}^{2}  \:  - \large\textsf{ \: 2a}

\large\textsf{                                                               }

 \qquad\tt{:}\longrightarrow -  \:  {\large\textsf{a}}^{2}  \:  +  \: \large\textsf{2a \:  + 8 \:  =  \: 0 }

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow -  \:  {\large\textsf{a}}^{2}  \: \large\textsf{ + 4a \:  -  \: 2a \:  + 8 \:  =  \: 0}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow \large\textsf{-  \: a \: ( \: a \:  -  \: 4 \: ) \:  -  \: 2 \: ( \: a \:  -  \: 4 \: ) \:  =  \: 0}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{( \: a \:  -  \: 4 \: )( \: a \:  -  \: 2 \:)  =  \: 0}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{a \:  -  \: 4 \:  =  \: 0 \:  \: or  \: \: a \:  -  \: 2 \:  =  \: 0}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{ a \:  =  \: 4 \:  \: or \:  \: a \:  =  \: 2}

\large\textsf{                                                               }

\boxed{\large\textsf{∴ The Value of a = 4 or 2}}

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