Question

If the distance between the point P( X, - 1), Q (3, 2) is 5, then the value of x is ​

Answer 1

Given: Two points P(x,-1)  and Q (3, 2)

To find: The value of x?

Solution:

Now we have given two points P(x,-1)  and Q (3, 2). The distance between them is 5 units.

Now we know the distance formula as:

                  PQ = √{ ( x2 - x1 )^2 + ( y2 - y1 )^2 }

So putting the values in formula, we get:

 5 = √{ ( 3 - x )^2 + ( 2 - (-1) )^2 }

5 = √{ ( 3 - x )^2 + ( 2 + 1) )^2 }

Squaring on both sides, we get:

   25 =  ( 3 - x )^2 + 9

 16 =  ( 3 - x )^2

 ( 3 - x ) = 4,-4

 x = -1 or x = 7

Ans

So the value of x is -1 or 7.

MARK AS BRAINLIST

Answer 2

Answer:

we know

• distance between points=Y2-Y1/X2-X1
• 2-(-1)/3-x=5,
• 3=15-5x,
• 5x=12,
• x=2.4